The challenge
Write evenOrOdd(n) that returns "even" or "odd". It must work for negative numbers too.
Try it
Write your answer below, then press Check my answer. Your code runs right here in your browser, and the tests tell you what works.
It prints
What the tests check
evenOrOdd(4)gives"even"evenOrOdd(7)gives"odd"evenOrOdd(0)gives"even"evenOrOdd(-3)gives"odd"
Hints
Stuck? Open one hint at a time. Try again after each one.
Hint 1
The remainder operator % tells you what’s left after dividing by 2.
Hint 2
Careful: -3 % 2 is -1, not 1. Checking n % 2 === 0 avoids that problem.
A solution
There’s always more than one right way. Read it, make sure you understand it, then try writing it yourself without looking.
Show one possible solution
function evenOrOdd(n) {
return n % 2 === 0 ? "even" : "odd";
}Learn what you need
This exercise uses what Grade 3: Operators: Math, Comparisons & Logic teaches. Read those notes first if any of it is new.